What is (\partial)/(\partial x)((x-b)/(b-c)) ?

The answer to (\partial)/(\partial x)((x-b)/(b-c)) is 1/(b-c)

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(\partial)/(\partial x)((x-b)/(b-c))

\frac{\partial}{\partial x} (\frac{x - b}{b - c})

\frac{1}{b - c}

Solution steps

\frac{\partial}{\partial x} (\frac{x - b}{b - c})

Treat

b, c

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{b - c} \frac{\partial}{\partial x} (x - b)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{b - c} (\frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (b))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (b) = 0

= \frac{1}{b - c} (1 - 0)

Simplify

= \frac{1}{b - c}

\frac{\partial}{\partial x} (x^{2} y + x sin (y))

f (x) = 7 x^{4} cot (x)

\frac{\partial}{\partial z} (- x z)

\int_{1}^{8} \frac{x ^{2} - 1}{x} d x

\frac{d}{d x} (y - x)

What is (\partial)/(\partial x)((x-b)/(b-c)) ?
The answer to (\partial)/(\partial x)((x-b)/(b-c)) is 1/(b-c)