What is the derivative of x^2+a*x+b ?

The derivative of x^2+a*x+b is 2x+a

What is the first derivative of x^2+a*x+b ?

The first derivative of x^2+a*x+b is 2x+a

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{2} + a \cdot x + b)

2 x + a

Solution steps

\frac{d}{d x} (x^{2} + a x + b)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (a x) + \frac{d b}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (a x) = a

\frac{d b}{d x} = 0

= 2 x + a + 0

Simplify

= 2 x + a

\frac{d y}{d x} = x^{2} (1 + y)

\frac{d}{d x} (ln (\frac{x + 3}{x - 3}))

\int \frac{1}{x 8 - ln ^{2} ( x ) + 2 ln ( x )} d x

x \to 0 + lim (6 x ln (x))

x \to - 2 lim (x^{2} - 4)

What is the derivative of x^2+a*x+b ?
The derivative of x^2+a*x+b is 2x+a
What is the first derivative of x^2+a*x+b ?
The first derivative of x^2+a*x+b is 2x+a