What is the derivative of arcsec(8x) ?

The derivative of arcsec(8x) is 1/(xsqrt(64x^2-1))

What is the first derivative of arcsec(8x) ?

The first derivative of arcsec(8x) is 1/(xsqrt(64x^2-1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (arcsec (8 x))

\frac{1}{x 64 x ^{2} - 1}

Solution steps

\frac{d}{d x} (arcsec (8 x))

Apply the chain rule:

\frac{1}{( 8 x ) ^{2} ( 8 x ) ^{2} - 1} \frac{d}{d x} (8 x)

= \frac{1}{( 8 x ) ^{2} ( 8 x ) ^{2} - 1} \frac{d}{d x} (8 x)

\frac{d}{d x} (8 x) = 8

= \frac{1}{( 8 x ) ^{2} ( 8 x ) ^{2} - 1} \cdot 8

Simplify

\frac{1}{( 8 x ) ^{2} ( 8 x ) ^{2} - 1} \cdot 8 : \frac{1}{x 64 x ^{2} - 1}

= \frac{1}{x 64 x ^{2} - 1}

\int - cos (x) + sin (x) + 5 d x

\int_{0}^{1} π (x - x^{2}) d x

x \to 2 lim (8 x + 3)

ln (10 x)

\int cos (sin (x)) cos (x) d x

What is the derivative of arcsec(8x) ?
The derivative of arcsec(8x) is 1/(xsqrt(64x^2-1))
What is the first derivative of arcsec(8x) ?
The first derivative of arcsec(8x) is 1/(xsqrt(64x^2-1))