What is the derivative of-2x^2+2x ?

The derivative of-2x^2+2x is -4x+2

What is the first derivative of-2x^2+2x ?

The first derivative of-2x^2+2x is -4x+2

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\frac{d}{d x} (- 2 x^{2} + 2 x)

- 4 x + 2

Solution steps

\frac{d}{d x} (- 2 x^{2} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (2 x) = 2

= - 4 x + 2

x \to 1 - lim (1 - e^{\frac{1}{x - 1}})

\int \frac{1}{17 - x ^{2}} d x

x e^{x}

\frac{d}{d x} ((ln (x^{5}))^{2})

What is the derivative of-2x^2+2x ?
The derivative of-2x^2+2x is -4x+2
What is the first derivative of-2x^2+2x ?
The first derivative of-2x^2+2x is -4x+2