What is the solution for (dy)/(dx)=e^{3x+y} ?

The solution for (dy)/(dx)=e^{3x+y} is y=-ln(-1/3 e^{3x}-c_{1})

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(dy)/(dx)=e^{3x+y}

\frac{d y}{d x} = e^{3 x + y}

y = - ln (- \frac{1}{3} e^{3 x} - c_{1})

Solution steps

\frac{d y}{d x} = e^{3 x + y}

Solve separable ODE:

y = - ln (- \frac{1}{3} e^{3 x} - c_{1})

y = - ln (- \frac{1}{3} e^{3 x} - c_{1})

k = 1 \sum \infty 0. 5^{k} T

\int_{- 1}^{1} \frac{x}{5 - 4 x} d x

\int_{0}^{2} 2 - x^{2} d x

t y^{^{'}} + 2 y = sin (t), y (\frac{π}{2}) = 1

f (x) = \frac{1}{x ^{\frac{2}{3}}}

What is the solution for (dy)/(dx)=e^{3x+y} ?
The solution for (dy)/(dx)=e^{3x+y} is y=-ln(-1/3 e^{3x}-c_{1})