What is (\partial)/(\partial y)(y/(x-1)) ?

The answer to (\partial)/(\partial y)(y/(x-1)) is 1/(x-1)

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(\partial)/(\partial y)(y/(x-1))

\frac{\partial}{\partial y} (\frac{y}{x - 1})

\frac{1}{x - 1}

Solution steps

\frac{\partial}{\partial y} (\frac{y}{x - 1})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{x - 1} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= \frac{1}{x - 1} \cdot 1

Simplify

= \frac{1}{x - 1}

y = e^{x^{3}}, (1, e)

\frac{e ^{x}}{6 + e ^{x}}

\frac{d}{d x} (\frac{1}{3 x - 4})

\frac{d}{d x} (2.2716 e^{0.2865 x})

\int x (x^{\frac{1}{3}} - x^{\frac{2}{5}}) d x

What is (\partial)/(\partial y)(y/(x-1)) ?
The answer to (\partial)/(\partial y)(y/(x-1)) is 1/(x-1)