What is the integral from 1 to 8 of x^{(-2)/3} ?

The integral from 1 to 8 of x^{(-2)/3} is 3

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integral from 1 to 8 of x^{(-2)/3}

\int_{1}^{8} x^{\frac{- 2}{3}} d x

3

Solution steps

\int_{1}^{8} x^{\frac{- 2}{3}} d x

Apply the Power Rule

: [3 x^{\frac{1}{3}}]_{1}^{8}

= [3 x^{\frac{1}{3}}]_{1}^{8}

Compute the boundaries:

3

= 3

e^{- x} sin (x)

f (x) = \frac{e ^{x}}{5 - 2 x}

\frac{d}{d x} (e^{x s i n (2 x)})

x \to 0 lim (x^{7} e^{- x^{6}})

\frac{1 + s}{s ^{3} - 2 s ^{2}}

What is the integral from 1 to 8 of x^{(-2)/3} ?
The integral from 1 to 8 of x^{(-2)/3} is 3