What is area y=9-0.25x^2,y=0,[2,5] ?

The answer to area y=9-0.25x^2,y=0,[2,5] is 17.25

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area y=9-0.25x^2,y=0,[2,5]

area

y = 9 - 0.25 x^{2}, y = 0, [2, 5]

17.25

Solution steps

Apply the area formula:

\int_{2}^{5} - 0.25 x^{2} + 9 d x

Solve

\int_{2}^{5} - 0.25 x^{2} + 9 d x : 17.25

The area is:

= 17.25

\frac{1}{3 x + 1}

\frac{d}{d x} ((2 x^{2} - 1)^{2} (7 x + 1)^{3})

f (x) = \frac{( x ^{2} )}{x ^{2} + 9}

\frac{d}{d y} (2 ln (3 x + 4 y))

x \to 0 lim (\frac{4 cos ( x - 4 )}{x})

What is area y=9-0.25x^2,y=0,[2,5] ?
The answer to area y=9-0.25x^2,y=0,[2,5] is 17.25