What is the sum from n=1 to infinity of 3(0.9)^{5-1} ?

The sum from n=1 to infinity of 3(0.9)^{5-1} is diverges

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sum from n=1 to infinity of 3(0.9)^{5-1}

n = 1 \sum \infty 3 (0.9)^{5 - 1}

diverges

Solution steps

n = 1 \sum \infty 3 \cdot 0. 9^{5 - 1}

Every infinite sum of a non-zero constant diverges

= diverges

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What is the sum from n=1 to infinity of 3(0.9)^{5-1} ?
The sum from n=1 to infinity of 3(0.9)^{5-1} is diverges