What is the derivative of cos^2(4x) ?

The derivative of cos^2(4x) is -4sin(8x)

What is the first derivative of cos^2(4x) ?

The first derivative of cos^2(4x) is -4sin(8x)

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\frac{d}{d x} (cos^{2} (4 x))

- 4 sin (8 x)

Solution steps

\frac{d}{d x} (cos^{2} (4 x))

Apply the chain rule:

2 cos (4 x) \frac{d}{d x} (cos (4 x))

= 2 cos (4 x) \frac{d}{d x} (cos (4 x))

\frac{d}{d x} (cos (4 x)) = - sin (4 x) \cdot 4

= 2 cos (4 x) (- sin (4 x) \cdot 4)

Simplify

2 cos (4 x) (- sin (4 x) \cdot 4) : - 4 sin (8 x)

= - 4 sin (8 x)

\frac{d}{d x} (\frac{x ^{2} + 2 x - 8}{x - 1})

arcsin (\frac{1}{x})

\frac{\partial}{\partial x} (ln (x^{2} + 1) + y^{2} - z)

\frac{\partial}{\partial x} (e^{z} (x - y)^{2})

x^{2} - 4, y = 0

What is the derivative of cos^2(4x) ?
The derivative of cos^2(4x) is -4sin(8x)
What is the first derivative of cos^2(4x) ?
The first derivative of cos^2(4x) is -4sin(8x)