What is the solution for (dy)/(dt)-3y=3e^{4t} ?

The solution for (dy)/(dt)-3y=3e^{4t} is y=3e^{4t}+c_{1}e^{3t}

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(dy)/(dt)-3y=3e^{4t}

\frac{d y}{d t} - 3 y = 3 e^{4 t}

y = 3 e^{4 t} + c_{1} e^{3 t}

Solution steps

\frac{d y}{d t} - 3 y = 3 e^{4 t}

Solve linear ODE:

y = 3 e^{4 t} + c_{1} e^{3 t}

y = 3 e^{4 t} + c_{1} e^{3 t}

y = 2 x^{2} lo g_{e} (x) - x^{2}

f (x) = e^{x}, at x = ln (7)

\frac{d y}{d x} = \frac{y}{x} + \frac{( y ^{2} )}{x ^{2}}

\frac{d}{d x} (\frac{3}{4 x - 5})

x y^{^{'}} = y ln (x y)

What is the solution for (dy)/(dt)-3y=3e^{4t} ?
The solution for (dy)/(dt)-3y=3e^{4t} is y=3e^{4t}+c_{1}e^{3t}