en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-3 to 1 of (x^2-4x)

Solution

\int_{- 3}^{1} (x^{2} - 4 x) d x

Solution

\frac{76}{3}

+1

Decimal Notation

25.33333 \dots

Solution steps

\int_{- 3}^{1} x^{2} - 4 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 3}^{1} x^{2} d x - \int_{- 3}^{1} 4 x d x

\int_{- 3}^{1} x^{2} d x = \frac{28}{3}

\int_{- 3}^{1} 4 x d x = - 16

= \frac{28}{3} - (- 16)

Simplify

\frac{28}{3} - (- 16) : \frac{76}{3}

= \frac{76}{3}

Popular Examples

derivative of ln(ln(x^2+1))

\frac{d}{d x} (ln (ln (x^{2} + 1)))

y^{^{''}} + a^{2} y = 0

x y^{^{''}} + 3 y^{^{'}} = 0

(\partial)/(\partial x)(ln(x^2-y))

\frac{\partial}{\partial x} (ln (x^{2} - y))

d/(dy)((y^3)/8)

\frac{d}{d y} (\frac{y ^{3}}{8})

Frequently Asked Questions (FAQ)

What is the integral from-3 to 1 of (x^2-4x) ?
The integral from-3 to 1 of (x^2-4x) is 76/3