What is the tangent of y=x^4+8x^2-x,(1,8) ?

The tangent of y=x^4+8x^2-x,(1,8) is y=19x-11

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tangent of y=x^4+8x^2-x,(1,8)

tangent of

y = x^{4} + 8 x^{2} - x, (1, 8)

y = 19 x - 11

Solution steps

Find the slope of

y = x^{4} + 8 x^{2} - x : \frac{d y}{d x} = 4 x^{3} + 16 x - 1

Compute the slope of

y = x^{4} + 8 x^{2} - x

(1, 8) : m = 19

Find the line with slope m=

19

and passing through

(1, 8) : y = 19 x - 11

y = 19 x - 11

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What is the tangent of y=x^4+8x^2-x,(1,8) ?
The tangent of y=x^4+8x^2-x,(1,8) is y=19x-11