What is the integral from-infinity to 0 of e^{-x^2} ?

The integral from-infinity to 0 of e^{-x^2} is (sqrt(pi))/2

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integral from-infinity to 0 of e^{-x^2}

\int_{- \infty}^{0} e^{- x^{2}} d x

\frac{π}{2}

Decimal Notation

0.88622 \dots

Solution steps

\int_{- \infty}^{0} e^{- x^{2}} d x

Compute the indefinite integral:

\int e^{- x^{2}} d x = \frac{π}{2} erf (x) + C

Compute the boundaries:

\int_{- \infty}^{0} e^{- x^{2}} d x = 0 - (- \frac{π}{2})

= 0 - (- \frac{π}{2})

Simplify

= \frac{π}{2}

\int x \cdot ln^{4} (x) d x

x \to 2 - lim (- \frac{1}{x - 2})

\frac{d}{d x} (- 4 cos (\frac{x}{2}))

y^{^{''}} - y^{^{'}} - 30 y = 0

\frac{16}{s ^{2} + 9}

What is the integral from-infinity to 0 of e^{-x^2} ?
The integral from-infinity to 0 of e^{-x^2} is (sqrt(pi))/2