What is the sum from n=0 to infinity of e^{-8n} ?

The sum from n=0 to infinity of e^{-8n} is converges

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sum from n=0 to infinity of e^{-8n}

n = 0 \sum \infty e^{- 8 n}

converges

Solution steps

n = 0 \sum \infty e^{- 8 n}

Apply Series Integral Test:

converges

= converges

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\frac{5 x ^{2}}{3 x - 1}

\int_{1}^{2} 3 - \frac{6}{x ^{2}} d x

\int \frac{6 cosh ( x )}{x} d x

y^{^{'''}} + 4 y^{^{''}} - 16 y^{^{'}} - 64 y = 0

What is the sum from n=0 to infinity of e^{-8n} ?
The sum from n=0 to infinity of e^{-8n} is converges