What is the solution for y^{''}+49y=cos(10t) ?

The solution for y^{''}+49y=cos(10t) is y=c_{1}cos(7t)+c_{2}sin(7t)-1/51 cos(10t)

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y^{''}+49y=cos(10t)

y^{^{''}} + 49 y = cos (10 t)

y = c_{1} cos (7 t) + c_{2} sin (7 t) - \frac{1}{51} cos (10 t)

Solution steps

y^{''} (t) + 49 y = cos (10 t)

Solve linear ODE:

y = c_{1} cos (7 t) + c_{2} sin (7 t) - \frac{1}{51} cos (10 t)

y = c_{1} cos (7 t) + c_{2} sin (7 t) - \frac{1}{51} cos (10 t)

ln (x^{3} + 5 x + 3)

x \to 1 lim (x sin (\frac{1}{x}))

y = x^{4} - 3 x^{2} + 2, (1, 0)

x \to 2 - lim (\frac{∣ x - x ∣}{x - 2})

\frac{d}{d x} (tan (3 x) s c^{3} x)

What is the solution for y^{''}+49y=cos(10t) ?
The solution for y^{''}+49y=cos(10t) is y=c_{1}cos(7t)+c_{2}sin(7t)-1/51 cos(10t)