What is the solution for y^{''}-4y=e^{2x} ?

The solution for y^{''}-4y=e^{2x} is y=c_{1}e^{2x}+c_{2}e^{-2x}+(e^{2x}x)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-4y=e^{2x}

y^{^{''}} - 4 y = e^{2 x}

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} + \frac{e ^{2 x} x}{4}

Solution steps

y^{''} (x) - 4 y = e^{2 x}

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} + \frac{e ^{2 x} x}{4}

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} + \frac{e ^{2 x} x}{4}

x \to 0 lim (sin (x^{x}))

\int \frac{1}{x ^{2} + 6 x + 58} d x

f (t) = sin^{2} (e^{s i n^{2} (t)})

\frac{2}{x}, at x = \frac{1}{4}

y = \frac{- 2 x}{x ^{2} + 1}, (1, - 1)

What is the solution for y^{''}-4y=e^{2x} ?
The solution for y^{''}-4y=e^{2x} is y=c_{1}e^{2x}+c_{2}e^{-2x}+(e^{2x}x)/4