What is the derivative of sqrt(2x^2+5) ?

The derivative of sqrt(2x^2+5) is (2x)/(sqrt(2x^2+5))

What is the first derivative of sqrt(2x^2+5) ?

The first derivative of sqrt(2x^2+5) is (2x)/(sqrt(2x^2+5))

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\frac{d}{d x} (2 x^{2} + 5)

\frac{2 x}{2 x ^{2} + 5}

Solution steps

\frac{d}{d x} (2 x^{2} + 5)

Apply the chain rule:

\frac{1}{2 2 x ^{2} + 5} \frac{d}{d x} (2 x^{2} + 5)

= \frac{1}{2 2 x ^{2} + 5} \frac{d}{d x} (2 x^{2} + 5)

\frac{d}{d x} (2 x^{2} + 5) = 4 x

= \frac{1}{2 2 x ^{2} + 5} \cdot 4 x

Simplify

\frac{1}{2 2 x ^{2} + 5} \cdot 4 x : \frac{2 x}{2 x ^{2} + 5}

= \frac{2 x}{2 x ^{2} + 5}

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\frac{d}{d x} (\frac{x sec ( - ( \frac{y}{x} ) + y )}{x})

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What is the derivative of sqrt(2x^2+5) ?
The derivative of sqrt(2x^2+5) is (2x)/(sqrt(2x^2+5))
What is the first derivative of sqrt(2x^2+5) ?
The first derivative of sqrt(2x^2+5) is (2x)/(sqrt(2x^2+5))