What is the integral of cotan^2(x) ?

The integral of cotan^2(x) is co(-x+tan(x))+C

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integral of cotan^2(x)

\int co tan^{2} (x) d x

co (- x + tan (x)) + C

Solution steps

\int co tan^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= co \cdot \int tan^{2} (x) d x

Rewrite using trig identities

= co \cdot \int - 1 + sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= co (- \int 1 d x + \int sec^{2} (x) d x)

\int 1 d x = x

\int sec^{2} (x) d x = tan (x)

= co (- x + tan (x))

Add a constant to the solution

= co (- x + tan (x)) + C

\frac{\partial}{\partial x} (\frac{1}{2 - x + y})

2 x + x^{2} - 5, at x = 1

y = \frac{x}{4 + x ^{2}}, (0, 0)

\int \frac{x ^{2} - 8}{x ^{4}} d x

\int_{0}^{1} (x^{3} - 3 x^{2}) d x

What is the integral of cotan^2(x) ?
The integral of cotan^2(x) is co(-x+tan(x))+C