What is the integral from 4 to 8 of 2/(x^3) ?

The integral from 4 to 8 of 2/(x^3) is 3/64

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integral from 4 to 8 of 2/(x^3)

\int_{4}^{8} \frac{2}{x ^{3}} d x

\frac{3}{64}

Decimal Notation

0.046875

Solution steps

\int_{4}^{8} \frac{2}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{4}^{8} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{4}^{8}

= 2 [- \frac{1}{2 x ^{2}}]_{4}^{8}

Compute the boundaries:

\frac{3}{128}

= 2 \cdot \frac{3}{128}

Simplify

= \frac{3}{64}

\int \frac{1}{24 x + 6 x ^{2}} d x

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x \to 0 lim (\frac{1}{x})

f (x) = \frac{tan ( x ) - 1}{sec ( x )}

\frac{\partial}{\partial y} (e^{y} \cdot cos (x))

What is the integral from 4 to 8 of 2/(x^3) ?
The integral from 4 to 8 of 2/(x^3) is 3/64