What is the first d/(dt)(e^{7t}) ?

The first d/(dt)(e^{7t}) is e^{7t}*7

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d/(dt)(e^{7t})

\frac{d}{d t} (e^{7 t})

e^{7 t} \cdot 7

Solution steps

\frac{d}{d t} (e^{7 t})

Apply the chain rule:

e^{7 t} \frac{d}{d t} (7 t)

= e^{7 t} \frac{d}{d t} (7 t)

\frac{d}{d t} (7 t) = 7

= e^{7 t} \cdot 7

\int \frac{1}{( x + 5 ) 10 x + x ^{2}} d x

\int 9 - x^{2} d x

- \frac{1}{x} 2

y = \frac{x}{x ^{2} + 1}

3 x^{2} - \frac{1}{x}