en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'-y=x,y(0)=1

Solution

y^{^{'}} - y = x, y (0) = 1

Solution

y = - x - 1 + 2 e^{x}

Solution steps

y^{'} (x) - y = x

Solve linear ODE:

y = - x - 1 + 2 e^{x}

y = - x - 1 + 2 e^{x}

Popular Examples

limit as x approaches-2 of x^3+8

x \to - 2 lim (x^{3} + 8)

integral of x(x-1)^4

\int x (x - 1)^{4} d x

derivative of f(x)=4^{x^9}derivative of

f (x) = 4^{x^{9}}

derivative of log_{e}(sqrt(x))

\frac{d}{d x} (lo g_{e} (x))

integral of 9/(x^2sqrt(x^2+16))

\int \frac{9}{x ^{2} x ^{2} + 16} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'-y=x,y(0)=1 ?
The solution for y^'-y=x,y(0)=1 is y=-x-1+2e^x