What is the derivative of tan^2(5θ) ?

The derivative of tan^2(5θ) is 10sec^2(5θ)tan(5θ)

What is the first derivative of tan^2(5θ) ?

The first derivative of tan^2(5θ) is 10sec^2(5θ)tan(5θ)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

tan^{2} (5 θ)

10 sec^{2} (5 θ) tan (5 θ)

Solution steps

\frac{d}{d θ} (tan^{2} (5 θ))

Apply the chain rule:

2 tan (5 θ) \frac{d}{d θ} (tan (5 θ))

= 2 tan (5 θ) \frac{d}{d θ} (tan (5 θ))

\frac{d}{d θ} (tan (5 θ)) = sec^{2} (5 θ) \cdot 5

= 2 tan (5 θ) sec^{2} (5 θ) \cdot 5

Simplify

= 10 sec^{2} (5 θ) tan (5 θ)

n = 1 \sum \infty 5 (- 1)^{n} n x^{n}

e^{- 4}

\frac{d}{d x} ((sin (x^{2}) + 1)^{\frac{1}{f ( x )}})

\int x^{2} x^{2} + 1 d x

- x^{3} + 2 x^{2} - 2, at x = 1

What is the derivative of tan^2(5θ) ?
The derivative of tan^2(5θ) is 10sec^2(5θ)tan(5θ)
What is the first derivative of tan^2(5θ) ?
The first derivative of tan^2(5θ) is 10sec^2(5θ)tan(5θ)