What is the derivative of 3x^3+4/x ?

The derivative of 3x^3+4/x is 9x^2-4/(x^2)

What is the first derivative of 3x^3+4/x ?

The first derivative of 3x^3+4/x is 9x^2-4/(x^2)

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derivative of

3 x^{3} + \frac{4}{x}

9 x^{2} - \frac{4}{x ^{2}}

Solution steps

\frac{d}{d x} (3 x^{3} + \frac{4}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) + \frac{d}{d x} (\frac{4}{x})

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= 9 x^{2} - \frac{4}{x ^{2}}

\frac{\partial}{\partial x} (x ln (y) - y^{2} 2^{x y})

y^{^{''}} + 9 y = - sin (3 x)

\int_{0}^{1} \frac{1}{x ^{2} - 2 x + 2} d x

\frac{\partial}{\partial φ} (ρ sin (φ) sin (θ))

y^{^{''}} - 4 y^{^{'}} + 4 y = \frac{e ^{2 x}}{x ^{2}}

What is the derivative of 3x^3+4/x ?
The derivative of 3x^3+4/x is 9x^2-4/(x^2)
What is the first derivative of 3x^3+4/x ?
The first derivative of 3x^3+4/x is 9x^2-4/(x^2)