What is the tangent of y= 7/(sqrt(x)),(4, 7/2) ?

The tangent of y= 7/(sqrt(x)),(4, 7/2) is y=-7/16 x+21/4

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tangent of y= 7/(sqrt(x)),(4, 7/2)

tangent of

y = \frac{7}{x}, (4, \frac{7}{2})

y = - \frac{7}{16} x + \frac{21}{4}

Solution steps

Find the slope of

y = \frac{7}{x} : \frac{d y}{d x} = - \frac{7}{2 x ^{\frac{3}{2}}}

Compute the slope of

y = \frac{7}{x}

(4, \frac{7}{2}) : m = - \frac{7}{16}

Find the line with slope m=

- \frac{7}{16}

and passing through

(4, \frac{7}{2}) : y = - \frac{7}{16} x + \frac{21}{4}

y = - \frac{7}{16} x + \frac{21}{4}

\frac{d}{d x} (50 - x^{2} - x)

x \to \frac{π}{2} lim (tan (x))

\frac{d}{d x} (64)

x = 10 y - y^{2}, x = y^{2} - 4 y

\int \frac{- 1000}{x ^{2}} d x

What is the tangent of y= 7/(sqrt(x)),(4, 7/2) ?
The tangent of y= 7/(sqrt(x)),(4, 7/2) is y=-7/16 x+21/4