What is the first derivative of 3x^2 ?

The first derivative of 3x^2 is 6x

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derivative of 3x^2

derivative of

3 x^{2}

6 x

Solution steps

\frac{d}{d x} (3 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 \cdot 2 x^{2 - 1}

Simplify

= 6 x

\int (2 x + 1)^{7} d x

\frac{d}{d x} (ln^{2} (sin (2 x)))

10 - x

\frac{d}{d y} ((\frac{1}{y ^{2}} - \frac{3}{y ^{4}}) (y + 7 y^{3}))

x \to \infty lim (e^{x})