What is the limit as x approaches+0 of x^2cos(1/x) ?

The limit as x approaches+0 of x^2cos(1/x) is 0

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limit as x approaches+0 of x^2cos(1/x)

x \to + 0 lim (x^{2} cos (\frac{1}{x}))

0

Solution steps

x \to 0 lim (x^{2} cos (\frac{1}{x}))

Apply the Squeeze Theorem:

0

= 0

\frac{d}{d x} (- 3 e^{- 2 x})

\int_{0}^{4} \frac{6 t}{( t - 5 ) ^{2}} d t

\int (- 2 x^{5} - 5 x^{3} + 3 x^{2} + 1 - 4 e^{x}) d x

\frac{d y}{d x} + (\frac{4}{76 + 3 x}) y = 4.2

\frac{d}{d x} (7 x - 2)

What is the limit as x approaches+0 of x^2cos(1/x) ?
The limit as x approaches+0 of x^2cos(1/x) is 0