What is the derivative of f(x)=5e^x+4/(\sqrt[3]{x)} ?

The derivative of f(x)=5e^x+4/(\sqrt[3]{x)} is 5e^x-4/(3x^{4/3)}

What is the first derivative of f(x)=5e^x+4/(\sqrt[3]{x)} ?

The first derivative of f(x)=5e^x+4/(\sqrt[3]{x)} is 5e^x-4/(3x^{4/3)}

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derivative of

5 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (5 e^{x}) = 5 e^{x}

= 5 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

\frac{d}{d t} (4 sin (t))

y^{^{''}} + 11 y^{^{'}} + 18 y = 0, y (0) = 1, y^{^{'}} (0) = 0

f (x) = - \frac{3}{2} x^{2}

\int_{- 1}^{0} t e^{- j^{2} π f t} d t

\frac{d}{d x} (6 x^{2} + 6 x - 36)

What is the derivative of f(x)=5e^x+4/(\sqrt[3]{x)} ?
The derivative of f(x)=5e^x+4/(\sqrt[3]{x)} is 5e^x-4/(3x^{4/3)}
What is the first derivative of f(x)=5e^x+4/(\sqrt[3]{x)} ?
The first derivative of f(x)=5e^x+4/(\sqrt[3]{x)} is 5e^x-4/(3x^{4/3)}