What is the integral of (x^2)/(y^2) ?

The integral of (x^2)/(y^2) is -(x^2)/y+C

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integral of (x^2)/(y^2)

\int \frac{x ^{2}}{y ^{2}} d y

- \frac{x ^{2}}{y} + C

Solution steps

\int \frac{x ^{2}}{y ^{2}} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= x^{2} \cdot \int \frac{1}{y ^{2}} d y

Apply the Power Rule

: - \frac{1}{y}

= x^{2} (- \frac{1}{y})

Simplify

x^{2} (- \frac{1}{y}) : - \frac{x ^{2}}{y}

= - \frac{x ^{2}}{y}

Add a constant to the solution

= - \frac{x ^{2}}{y} + C

\int 10 x^{4} - sec^{2} (x) d x

\frac{d}{d x} (x^{3} (3 x^{6} - 5 x^{2} + 4))

y = x, y = x, x = 4

\int \frac{1}{3} (1 - x^{2})^{3} d x

cos (x) \frac{d y}{d x} + (sin (x)) y = 1