What is the solution for (x^2+1)(dy)/(dx)+5x(y-1)=0 ?

The solution for (x^2+1)(dy)/(dx)+5x(y-1)=0 is y=(c_{1})/((x^2+1)^{5/2)}+1

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(x^2+1)(dy)/(dx)+5x(y-1)=0

(x^{2} + 1) \frac{d y}{d x} + 5 x (y - 1) = 0

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{5}{2}}} + 1

Solution steps

(x^{2} + 1) \frac{d y}{d x} + 5 x (y - 1) = 0

Solve separable ODE:

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{5}{2}}} + 1

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{5}{2}}} + 1

2 y^{^{''}} - 11 y^{^{'}} - 6 y = 0

\int_{0}^{1} 7 \frac{1}{x ^{p}} d x

x \to 3 lim (x^{3})

\int \frac{x + 2}{2 x + 2} d x

x \to 2 - lim (\frac{9 x}{x - 2})

What is the solution for (x^2+1)(dy)/(dx)+5x(y-1)=0 ?
The solution for (x^2+1)(dy)/(dx)+5x(y-1)=0 is y=(c_{1})/((x^2+1)^{5/2)}+1