What is the integral of e^{xt} ?

The integral of e^{xt} is 1/t e^{tx}+C

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integral of e^{xt}

\int e^{x t} d x

\frac{1}{t} e^{t x} + C

Solution steps

\int e^{x t} d x

Apply u-substitution

: \int \frac{e ^{u}}{t} d u

= \int \frac{e ^{u}}{t} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{t} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{t} e^{u}

Substitute back

u = t x

= \frac{1}{t} e^{t x}

Add a constant to the solution

= \frac{1}{t} e^{t x} + C

x \to 10 lim ((3 - \frac{4}{5} x) + 5)

\frac{d}{d x} ((arcsin (2 x))^{2})

e^{- 3 t}, at t = 0

\frac{d}{d x} (- 5 cos (x))

π^{2}