What is the derivative of 2e^{3t}-e^{2t} ?

The derivative of 2e^{3t}-e^{2t} is 6e^{3t}-e^{2t}*2

What is the first derivative of 2e^{3t}-e^{2t} ?

The first derivative of 2e^{3t}-e^{2t} is 6e^{3t}-e^{2t}*2

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derivative of

2 e^{3 t} - e^{2 t}

6 e^{3 t} - e^{2 t} \cdot 2

Solution steps

\frac{d}{d t} (2 e^{3 t} - e^{2 t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2 e^{3 t}) - \frac{d}{d t} (e^{2 t})

\frac{d}{d t} (2 e^{3 t}) = 6 e^{3 t}

\frac{d}{d t} (e^{2 t}) = e^{2 t} \cdot 2

= 6 e^{3 t} - e^{2 t} \cdot 2

\int_{e^{x}}^{0} sin^{3} (t) d t

\int \frac{32}{x ( x ^{2} + 4 ) ^{2}} d x

y = x^{2}, y = x, 0.25, 1

\frac{x ^{2} - 3 x + 8}{x ^{2} + 9}

x^{4 x}

What is the derivative of 2e^{3t}-e^{2t} ?
The derivative of 2e^{3t}-e^{2t} is 6e^{3t}-e^{2t}*2
What is the first derivative of 2e^{3t}-e^{2t} ?
The first derivative of 2e^{3t}-e^{2t} is 6e^{3t}-e^{2t}*2