What is area x^3-6x^2+9x+1,x=0.5,x=4 ?

The answer to area x^3-6x^2+9x+1,x=0.5,x=4 is 10.609375

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area x^3-6x^2+9x+1,x=0.5,x=4

area

x^{3} - 6 x^{2} + 9 x + 1, x = 0.5, x = 4

10.609375

Solution steps

Apply the area formula:

\int_{0.5}^{4} x^{3} - 6 x^{2} + 9 x + 1 d x

Solve

\int_{0.5}^{4} x^{3} - 6 x^{2} + 9 x + 1 d x : 10.609375

The area is:

= 10.609375

f (x) = x^{2} + x, at x = - 4

\int_{0}^{1} e^{x} d x

e^{x^{2}}

18 (x^{2} + 6)^{8}

\int \frac{x ^{2} - 7}{( x - 2 ) ( x + 1 )} d x

What is area x^3-6x^2+9x+1,x=0.5,x=4 ?
The answer to area x^3-6x^2+9x+1,x=0.5,x=4 is 10.609375