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Popular >

integral of 1-y^2

Solution

\int 1 - y^{2} d y

Solution

y - \frac{y ^{3}}{3} + C

Solution steps

\int 1 - y^{2} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d y - \int y^{2} d y

\int 1 d y = y

\int y^{2} d y = \frac{y ^{3}}{3}

= y - \frac{y ^{3}}{3}

Add a constant to the solution

= y - \frac{y ^{3}}{3} + C

Popular Examples

area y=7\sqrt[3]{x},0<= x<= 27 area

integral of 1/(f(f-u))

\int \frac{1}{f ( f - u )} df

integral from 1 to 5 of (4x-4/x)

\int_{1}^{5} (4 x - \frac{4}{x}) d x

inverse oflaplace 2/(s^2+2s+3)inverse laplace

\frac{2}{s ^{2} + 2 s + 3}

inverse oflaplace (-1+3s^2)/(s*(s^2-1))inverse laplace

\frac{- 1 + 3 s ^{2}}{s \cdot ( s ^{2} - 1 )}

Frequently Asked Questions (FAQ)

What is the integral of 1-y^2 ?
The integral of 1-y^2 is y-(y^3)/3+C