What is the tangent of y=x^2-2x+1,(-1,4) ?

The tangent of y=x^2-2x+1,(-1,4) is y=-4x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=x^2-2x+1,(-1,4)

tangent of

y = x^{2} - 2 x + 1, (- 1, 4)

y = - 4 x

Solution steps

Find the slope of

y = x^{2} - 2 x + 1 : \frac{d y}{d x} = 2 x - 2

Compute the slope of

y = x^{2} - 2 x + 1

(- 1, 4) : m = - 4

Find the line with slope m=

- 4

and passing through

(- 1, 4) : y = - 4 x

y = - 4 x

\frac{\partial}{\partial x} (5^{8^{x^{2}}})

\int (e^{x} + 1) \cdot (x - 4) d x

\frac{d y}{d x} - \frac{1}{x} y = 1 - \frac{1}{x}

f (x) = 25 - x^{2}, (5, 0)

What is the tangent of y=x^2-2x+1,(-1,4) ?
The tangent of y=x^2-2x+1,(-1,4) is y=-4x