What is the solution for y^'=(x+y+7)^2 ?

The solution for y^'=(x+y+7)^2 is y=tan(x+c_{1})-x-7

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y^'=(x+y+7)^2

y^{^{'}} = (x + y + 7)^{2}

y = tan (x + c_{1}) - x - 7

Solution steps

y^{'} (x) = (x + y + 7)^{2}

Solve using substitution:

y = tan (x + c_{1}) - x - 7

y = tan (x + c_{1}) - x - 7

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3 (1 + 8 e^{- \frac{t}{2}} - 9 e^{- t})

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What is the solution for y^'=(x+y+7)^2 ?
The solution for y^'=(x+y+7)^2 is y=tan(x+c_{1})-x-7