What is the integral of (x^2-3/x) ?

The integral of (x^2-3/x) is (x^3)/3-3ln|x|+C

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integral of (x^2-3/x)

\int (x^{2} - \frac{3}{x}) d x

\frac{x ^{3}}{3} - 3 ln ∣ x ∣ + C

Solution steps

\int x^{2} - \frac{3}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int \frac{3}{x} d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int \frac{3}{x} d x = 3 ln ∣ x ∣

= \frac{x ^{3}}{3} - 3 ln ∣ x ∣

Add a constant to the solution

= \frac{x ^{3}}{3} - 3 ln ∣ x ∣ + C

n = 0 \sum \infty \frac{1}{3 n}

y = \frac{( 3 x - 6 )}{( x ^{2} + 4 )}

x^{2} + y^{3} = 12

\frac{d}{d x} (9 e^{x} + 5)

\frac{16}{( s + 4 ) ^{2}}

What is the integral of (x^2-3/x) ?
The integral of (x^2-3/x) is (x^3)/3-3ln|x|+C