What is the integral from 0 to 1 of cos(2pix) ?

The integral from 0 to 1 of cos(2pix) is 0

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integral from 0 to 1 of cos(2pix)

\int_{0}^{1} cos (2 π x) d x

0

Solution steps

\int_{0}^{1} cos (2 π x) d x

Apply u-substitution

: \int_{0}^{2 π} cos (u) \frac{1}{2 π} d u

= \int_{0}^{2 π} cos (u) \frac{1}{2 π} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2 π} \cdot \int_{0}^{2 π} cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{2 π} [sin (u)]_{0}^{2 π}

Compute the boundaries:

0

= \frac{1}{2 π} \cdot 0

Simplify

= 0

x \to 3 lim (x - 1)

y^{^{''}} + 36 y = - 48 sin (6 t)

\frac{d}{d x} (x^{2} + x - 6)

f (x) = (3 x^{2} - 4 x) e^{x}

(x - x) (x + x)

What is the integral from 0 to 1 of cos(2pix) ?
The integral from 0 to 1 of cos(2pix) is 0