What is the integral of 4x^3-3x^2+5 ?

The integral of 4x^3-3x^2+5 is x^4-x^3+5x+C

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integral of 4x^3-3x^2+5

\int 4 x^{3} - 3 x^{2} + 5 d x

x^{4} - x^{3} + 5 x + C

Solution steps

\int 4 x^{3} - 3 x^{2} + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{3} d x - \int 3 x^{2} d x + \int 5 d x

\int 4 x^{3} d x = x^{4}

\int 3 x^{2} d x = x^{3}

\int 5 d x = 5 x

= x^{4} - x^{3} + 5 x

Add a constant to the solution

= x^{4} - x^{3} + 5 x + C

\int (3 x^{2} y^{- 2} + 2 x y^{- 1}) d x

\frac{d}{d x} (\frac{( x + 1 ) ( 3 x - 7 )}{3 x + 1})

\int_{- 2}^{2} (x^{2} - 2)^{2} d x

\frac{d}{d x} (1 - (1 - 0.01 x)^{3})

\frac{\partial}{\partial x} (2 y x^{2} + 4)

What is the integral of 4x^3-3x^2+5 ?
The integral of 4x^3-3x^2+5 is x^4-x^3+5x+C