What is area y^2=x+10,y^2=8-x ?

The answer to area y^2=x+10,y^2=8-x is No Solution

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area y^2=x+10,y^2=8-x

area

y^{2} = x + 10, y^{2} = 8 - x

No Solution

Solution steps

Isolate

y

for

y^{2} = x + 10 : y = x + 10, y = - x + 10

Isolate

y

for

y^{2} = 8 - x : y = 8 - x, y = - 8 - x

f_{1} (x) = x + 10

f_{2} (x) = - x + 10

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x + 10 = - x + 10 : x = - 10

x + 10 = 8 - x : x = - 1

x + 10 = - 8 - x :

No Solution for

x \in R

- x + 10 = 8 - x :

No Solution for

x \in R

- x + 10 = - 8 - x : x = - 1

8 - x = - 8 - x : x = 8

Curves not bounded

= No Solution

\frac{\partial}{\partial x} (\frac{1}{( x + y ) ^{2}})

x \to 1 lim (\frac{1}{1 + x ^{2}})

- 4 x^{2} + 9, x + 7, 0

x^{9}

\frac{d}{d x} (\frac{( x ^{2} - 5 ) ^{3}}{( x ^{2} + 4 ) ^{2}})

What is area y^2=x+10,y^2=8-x ?
The answer to area y^2=x+10,y^2=8-x is No Solution