What is the derivative of f(x)=3x^2+x+5 ?

The derivative of f(x)=3x^2+x+5 is 6x+1

What is the first derivative of f(x)=3x^2+x+5 ?

The first derivative of f(x)=3x^2+x+5 is 6x+1

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derivative of

f (x) = 3 x^{2} + x + 5

6 x + 1

Solution steps

\frac{d}{d x} (3 x^{2} + x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d x}{d x} + \frac{d}{d x} (5)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d x}{d x} = 1

\frac{d}{d x} (5) = 0

= 6 x + 1 + 0

Simplify

= 6 x + 1

f (x) = - 5 x^{2} + 2 x - 6

x \to 0 + lim (\frac{∣ x - 0 ∣}{0 - x})

\int_{2}^{\infty} x e^{- 4 x} d x

\int 3 e^{2 x^{3} + 3 x^{2} - 9} (x^{2} + x) d x

\int \frac{8 x ^{3}}{e ^{x^{4}}} d x

What is the derivative of f(x)=3x^2+x+5 ?
The derivative of f(x)=3x^2+x+5 is 6x+1
What is the first derivative of f(x)=3x^2+x+5 ?
The first derivative of f(x)=3x^2+x+5 is 6x+1