What is the integral from 0 to 1.5 of 70x ?

The integral from 0 to 1.5 of 70x is 78.75

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integral from 0 to 1.5 of 70x

\int_{0}^{1.5} 70 x d x

78.75

Solution steps

\int_{0}^{1.5} 70 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 70 \cdot \int_{0}^{1.5} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1.5}

= 70 [\frac{x ^{2}}{2}]_{0}^{1.5}

Simplify

= 70 [0.5 x^{2}]_{0}^{1.5}

Compute the boundaries:

1.125

= 70 \cdot 1.125

Simplify

= 78.75

\int (x sin (x y)) d x

\frac{d}{d x} (\frac{3}{2 x ^{3}})

\frac{d}{d t} (\frac{t}{1 + t ^{2}})

y^{^{'}} + 3.25 y = 26

\frac{d}{d x} (a x b)

What is the integral from 0 to 1.5 of 70x ?
The integral from 0 to 1.5 of 70x is 78.75