What is derivative of f(x)=(2^{5t})/t ?

The answer to derivative of f(x)=(2^{5t})/t is (dt)/(dx)=0

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derivative of f(x)=(2^{5t})/t

derivative of

f (x) = \frac{2 ^{5 t}}{t}

\frac{d t}{d x} = 0

Solution steps

f (x) = \frac{2 ^{5 t}}{t}

Treat

t

t (x)

Differentiate both sides:

0 = \frac{5 ln ( 2 ) \cdot 3 2 ^{t} \frac{d t}{d x} t - 3 2 ^{t} \frac{d t}{d x}}{t ^{2}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\frac{d}{d x} (4 x^{3} ln (x) + x^{3})

\int \frac{1}{( 5 x - 4 ) ^{10}} d x

y = (- 5)^{2} - 9 (- 5)

\int \frac{2 x + 7}{x + 3} d x

\int \frac{1}{x ^{2} x ^{2} - 10} d x

What is derivative of f(x)=(2^{5t})/t ?
The answer to derivative of f(x)=(2^{5t})/t is (dt)/(dx)=0