What is maclaurin 8/(3x+3) ?

The answer to maclaurin 8/(3x+3) is 8/3-8/3 x+8/3 x^2-8/3 x^3+8/3 x^4+\ldots

Popular >

maclaurin 8/(3x+3)

maclaurin

\frac{8}{3 x + 3}

\frac{8}{3} - \frac{8}{3} x + \frac{8}{3} x^{2} - \frac{8}{3} x^{3} + \frac{8}{3} x^{4} + \dots

Solution steps

Apply the Maclaurin Formula

= \frac{8}{3} + \frac{\frac{d}{d x} ( \frac{8}{3 x + 3} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{8}{3 x + 3} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{8}{3 x + 3} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= \frac{8}{3} + \frac{- \frac{8}{3}}{1 !} x + \frac{\frac{16}{3}}{2 !} x^{2} + \frac{- 16}{3 !} x^{3} + \frac{64}{4 !} x^{4} + \dots

Refine

= \frac{8}{3} - \frac{8}{3} x + \frac{8}{3} x^{2} - \frac{8}{3} x^{3} + \frac{8}{3} x^{4} + \dots

f (x) = \frac{6 cos ( x )}{7 - 9 cos ( x )}

\int \frac{1 - x + 2 x ^{2} - x ^{3}}{x ( x ^{2} + 1 ) ^{2}} d x

cos (2 x^{2})

\int_{0}^{2} \frac{3 ln ( x )}{x} d x

\frac{d}{d x} (\frac{1}{4} e^{x})

What is maclaurin 8/(3x+3) ?
The answer to maclaurin 8/(3x+3) is 8/3-8/3 x+8/3 x^2-8/3 x^3+8/3 x^4+\ldots