What is derivative of f(x)=4t^{-1/8} ?

The answer to derivative of f(x)=4t^{-1/8} is (dt)/(dx)=0

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derivative of f(x)=4t^{-1/8}

derivative of

f (x) = 4 t^{- \frac{1}{8}}

\frac{d t}{d x} = 0

Solution steps

f (x) = 4 t^{- \frac{1}{8}}

Treat

t

t (x)

Differentiate both sides:

0 = - \frac{\frac{d t}{d x}}{2 t ^{\frac{9}{8}}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\int \frac{1}{12 y - 10 y ^{2}} d y

\int \frac{sin ( x )}{x ^{3}} d x

f (x) = cos (cos (cos (x)))

n = 1 \sum \infty \frac{6}{( n + 1 ) !}

y^{^{''}} = a (y^{^{'}})^{2} + b

What is derivative of f(x)=4t^{-1/8} ?
The answer to derivative of f(x)=4t^{-1/8} is (dt)/(dx)=0