What is the solution for (dy)/(dx)=(yx-y^2)/(x^2+yx) ?

The solution for (dy)/(dx)=(yx-y^2)/(x^2+yx) is y= x/(\W(\frac{x^2){c_{1}})}

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(dy)/(dx)=(yx-y^2)/(x^2+yx)

\frac{d y}{d x} = \frac{y x - y ^{2}}{x ^{2} + y x}

y = \frac{x}{W ( \frac{x ^{2}}{c _{1}} )}

Solution steps

\frac{d y}{d x} = \frac{y x - y ^{2}}{x ^{2} + y x}

Solve using substitution:

y = \frac{x}{W ( \frac{x ^{2}}{c _{1}} )}

y = \frac{x}{W ( \frac{x ^{2}}{c _{1}} )}

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What is the solution for (dy)/(dx)=(yx-y^2)/(x^2+yx) ?
The solution for (dy)/(dx)=(yx-y^2)/(x^2+yx) is y= x/(\W(\frac{x^2){c_{1}})}