What is the derivative of f(x)=e^{2x}-1 ?

The derivative of f(x)=e^{2x}-1 is 2e^{2x}

What is the first derivative of f(x)=e^{2x}-1 ?

The first derivative of f(x)=e^{2x}-1 is 2e^{2x}

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derivative of

f (x) = e^{2 x} - 1

2 e^{2 x}

Solution steps

\frac{d}{d x} (e^{2 x} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{2 x}) - \frac{d}{d x} (1)

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

\frac{d}{d x} (1) = 0

= e^{2 x} \cdot 2 - 0

Simplify

= 2 e^{2 x}

n = 1 \sum \infty - n

x \to 0 lim (\frac{sin ( 3 x ^{2} )}{ln ( x ^{2} + 1 )})

\frac{d}{d x} (\frac{x}{( x ^{2} + y ^{2} ) ^{\frac{3}{2}}})

e^{t a n (θ)}

\frac{\partial}{\partial x} (y ln (3 x + 5 y))

What is the derivative of f(x)=e^{2x}-1 ?
The derivative of f(x)=e^{2x}-1 is 2e^{2x}
What is the first derivative of f(x)=e^{2x}-1 ?
The first derivative of f(x)=e^{2x}-1 is 2e^{2x}