What is (\partial)/(\partial v)(4usin(v)) ?

The answer to (\partial)/(\partial v)(4usin(v)) is 4ucos(v)

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(\partial)/(\partial v)(4usin(v))

\frac{\partial}{\partial v} (4 u sin (v))

4 u cos (v)

Solution steps

\frac{\partial}{\partial v} (4 u sin (v))

Treat

u

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 u \frac{\partial}{\partial v} (sin (v))

Apply the common derivative:

\frac{\partial}{\partial v} (sin (v)) = cos (v)

= 4 u cos (v)

\int x x - 15 d x

\int x e^{x y} d y

\int e^{x + 1} d x

\frac{d}{d x} (\frac{2}{x ^{2} + 4})

f (t) = t^{3} e^{- 2 t} cos (6 t)

What is (\partial)/(\partial v)(4usin(v)) ?
The answer to (\partial)/(\partial v)(4usin(v)) is 4ucos(v)