What is the derivative of 1/((t^2+3t+1)^{5/2)} ?

The derivative of 1/((t^2+3t+1)^{5/2)} is -(5(2t+3))/(2(t^2+3t+1)^{7/2)}

What is the first derivative of 1/((t^2+3t+1)^{5/2)} ?

The first derivative of 1/((t^2+3t+1)^{5/2)} is -(5(2t+3))/(2(t^2+3t+1)^{7/2)}

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derivative of

\frac{1}{( t ^{2} + 3 t + 1 ) ^{\frac{5}{2}}}

- \frac{5 ( 2 t + 3 )}{2 ( t ^{2} + 3 t + 1 ) ^{\frac{7}{2}}}

Solution steps

\frac{d}{d t} (\frac{1}{( t ^{2} + 3 t + 1 ) ^{\frac{5}{2}}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d t} ((t^{2} + 3 t + 1)^{- \frac{5}{2}})

Apply the chain rule:

- \frac{5}{2 ( t ^{2} + 3 t + 1 ) ^{\frac{7}{2}}} \frac{d}{d t} (t^{2} + 3 t + 1)

= - \frac{5}{2 ( t ^{2} + 3 t + 1 ) ^{\frac{7}{2}}} \frac{d}{d t} (t^{2} + 3 t + 1)

\frac{d}{d t} (t^{2} + 3 t + 1) = 2 t + 3

= - \frac{5}{2 ( t ^{2} + 3 t + 1 ) ^{\frac{7}{2}}} (2 t + 3)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{5 ( 2 t + 3 )}{2 ( t ^{2} + 3 t + 1 ) ^{\frac{7}{2}}}

y = x^{4} + 8 x^{2} - x

\int 2 x^{3} - \frac{2}{3} x^{2} + 7 x d x

n = 0 \sum \infty \frac{8}{4 ^{n}}

\frac{\partial}{\partial x} (- sin (x^{2} y) x^{2})

\int t \cdot \frac{1}{e ^{t}} d t

What is the derivative of 1/((t^2+3t+1)^{5/2)} ?
The derivative of 1/((t^2+3t+1)^{5/2)} is -(5(2t+3))/(2(t^2+3t+1)^{7/2)}
What is the first derivative of 1/((t^2+3t+1)^{5/2)} ?
The first derivative of 1/((t^2+3t+1)^{5/2)} is -(5(2t+3))/(2(t^2+3t+1)^{7/2)}