What is the solution for (dx)/(dt)=((2t^2+x^2))/(tx) ?

The solution for (dx)/(dt)=((2t^2+x^2))/(tx) is x=tsqrt(4ln(t)+c_{1)},x=-tsqrt(4ln(t)+c_{1)}

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(dx)/(dt)=((2t^2+x^2))/(tx)

\frac{d x}{d t} = \frac{( 2 t ^{2} + x ^{2} )}{t x}

x = t 4 ln (t) + c_{1}, x = - t 4 ln (t) + c_{1}

Solution steps

\frac{d x}{d t} = \frac{( 2 t ^{2} + x ^{2} )}{t x}

Solve Bernoulli ODE:

x = t 4 ln (t) + c_{1}, x = - t 4 ln (t) + c_{1}

x = t 4 ln (t) + c_{1}, x = - t 4 ln (t) + c_{1}

y^{^{''}} - 2 y^{^{'}} + 5 y = e^{x} sin (x)

\int_{0}^{\infty} 1 d x

\int e^{- s t} - t e^{- s t} d t

y = x^{3} - x, y = 3 x

\int_{- \infty}^{0} \frac{1}{5 - 6 x} d x

What is the solution for (dx)/(dt)=((2t^2+x^2))/(tx) ?
The solution for (dx)/(dt)=((2t^2+x^2))/(tx) is x=tsqrt(4ln(t)+c_{1)},x=-tsqrt(4ln(t)+c_{1)}